We change the % RH from 50% RH to 90% RH : Now we see what happens when we change the condition of the block 'source' Now we simulate the same cooling with 2 kg of moist air:
To the heat output of the previous problem While absolute humidity remains the same at 7.26 g / kg The air has become much wetter, with 95% RH,īut not yet condensed (condensation limit is 100% RH) the cooling capacity is equal When the temperature is cooling from 20 ' C to 10 ' C the % RH rise from 50% to 95.2% RH Under the calculation column, you will see that the block automatically calculates Then we set the parameter of the cooling block -10 'C. Then we set the parameters to 20 'C and 50% RH and the Flow 2 kg / s We place a block air source and a cooling block and connect them with each other.
What happens when 2 kg of air is cooled from 20 'C to 10'C ? This method is shown in the second model alongside.
That gives 2 kg / s> (2/1.2) * 3600 = 6000 m3/hr.Ī better way is to get out of the heat content of air enthalpy h = Q = (29.6 kJ - 19.5 kJ) * 2 kg / s = 20.15 kW. Note: these blocks do not affect the model / process and are purely for the measurement of variables / units.Īmount of heat flow Q is Q = mass * specific heat * vd air temperature Q = 2kg / s * 1007 * 10 = 20 kW Density at 20 ' C as per 1 m3 of air is 1.2 kg. When we want to calculate the power we place additional blocks for measuring the required units for power. While absolute humidity remains the same 3.8 g / kg. The 'heater' block is calculated itself you can see what happens with the air of 10 ' C when it is heated to 20 ' C. See that it automatically calculates what the air is doing. Heater block: Then we give in parameter for the heater in the block 'heater'. Then we connect these blocks so that air can be heatedĪir block: Here we set the parameters for the initial situation at 10 ' C and 50% RH (relative humidity) and Flow 2 kg / s. With HVAC Simply the process of heating of air can be easily modeling by a block 'Source air' and a block 'heater' place on the grid. With HVAC Simply the above process can be modeling and automatic calculated how much power is needed for this,Īnd what happens to the relative humidity during this process HVAC Simply solution: A simpler solution is to use HVAC Simply. This problem can be solved using a Mollier Diagram. What happens to the humidity when 2 kg of air is heated from 10 ' C to 20 'C ? Solving various issues with using HVAC Simply simulation software
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